Question

The following is the graph of

Answer 1

look at graph

Answer 2

@BioHazard9064

Answer 3

wow

Answer 4

im over thinking it? or wow its hard..

Answer 5

I would say false

Answer 6

why?

Answer 7

actually it is true
it looks just like the graph of \(y=\sqrt[3]{x}\) only shifted to the right three units, which is what happens when you do
\[y=\sqrt[3]{x-3}\]

Answer 8

i graphed it but I could be wrong

Answer 9

oh i over looked the first 3 xD

Answer 10

you are supposed to know two things hers
a) what \(y=\sqrt[3]{x}\) looks like and
b) what happens when you replace \(x\) by \(x-3\)

Answer 11

so it true?

Answer 12

The domain should be x >= 3 since rooting negatives results in imaginary numbers, so I think the graph should have started at x=3 if the graph was true

Answer 13

so false?

Answer 14

I would say yes. because everything before x=3 should not be graphed