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CHEM II CHALLENGE: Solve #2 & #3! http://i.imgur.com/iyZiO0U.jpg
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Solved #3a, using the Nernst equation I get .0058V Ecell=Eo-(.0592/n)logQ n=1 because AgNO3>Ag(+)+NO3(-) with 1 electron transported .065=Eo-(.0592/1)log(1/.1) Eo=.1242 .1242-(.0592/1)log(.1/.01)=.0058V
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