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Chemistry 7 Online
OpenStudy (anonymous):

Use the information for the isotopes of X to calculate the average atomic mass of X, and identify the element. Isotope Abundance Mass (amu) 6X 7.5% 6.015 7X 92.5% 7.016 I'm kinda confused :/

OpenStudy (zale101):

\(Average ~atomic~ mass~ of~ an ~element\) = \( (Abundance~percentage_1*Mass~of~Isotope~ 1)\) + \((Abundance~percentage_2*Mass~of~Isotope~ 2))\)

OpenStudy (anonymous):

So would I have to calculate that like 7.5 * 6.015, and the same for the other one?

OpenStudy (photon336):

You would add the two masses together

OpenStudy (zale101):

Correct. You'll add it with Isotope 7x to get the average atomic mass of the element

OpenStudy (photon336):

but first you need to multiply the atomic mass by the % abundance I believe

OpenStudy (anonymous):

So it's 45.1125 + 648.98 ?

OpenStudy (anonymous):

@Photon336 would it be 694.0925?

OpenStudy (photon336):

@Zale101 6X and 7X are just the names of the isotopes right?

OpenStudy (zale101):

I believe so.

OpenStudy (anonymous):

Yeah they are...

OpenStudy (photon336):

yeah.. so convert 7.5% to decimal form which is 7.5/100 then you multiply this by 6.015 amu

OpenStudy (photon336):

remember @flatouthero its' a percentage

OpenStudy (anonymous):

Oh, so it's 6.94

OpenStudy (zale101):

Correct!

OpenStudy (zale101):

:)

OpenStudy (zale101):

What element is that?

OpenStudy (anonymous):

Thank you both for your help!

OpenStudy (photon336):

no problem

OpenStudy (anonymous):

Lithium, btw xD

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