Question

Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.

Answer 1

Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.

177,147
88,572<---my answer
88,575
177,144

Answer 2

first term = a = 3
10th term = ar^9 = 59,049

ar^9 / a = r^9

r^9 = 59049 / 3= 19683

r = ninth root of 19683

use ur calc to find this

Answer 3

88,575 is what I got :) Am I right?

Answer 4

@Mehek14

Answer 5

S10 = 3 * 3^10 - 1
-------
3 - 1

Answer 6

88573

Answer 7

i make it 88572

Answer 8

177146/2=88572 :) Thanks so much!

Answer 9

yw