Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.

Question

anonymous · Answer

Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.

 177,147
 88,572<---my answer 
 88,575
 177,144

welshfella · Answer

first term = a = 3
10th term = ar^9 = 59,049

ar^9 / a = r^9 

r^9 = 59049 / 3= 19683

r = ninth root of 19683

use ur calc to find this

anonymous · Answer

88,575 is what I got :) Am I right?

anonymous · Answer

@Mehek14

welshfella · Answer

S10  = 3 * 3^10 - 1
                 -------
                     3 - 1

anonymous · Answer

88573

welshfella · Answer

i make it 88572

anonymous · Answer

177146/2=88572 :) Thanks so much!

welshfella · Answer

yw