Question

Factor x^2-12x+36-49y^2

Answer 1

I have x^2+24x-49y^2 so far

Answer 2

\[a^2-b^2=\left( a+b \right)\left( a-b \right)\]
\[x^2-12x+36-49y^2=\left( x-6 \right)^2-\left( 7y \right)^2=?\]

Answer 3

um x^2-12x-36-49y^2

Answer 4

I'm lost

Answer 5

Hint:


\[\Large (x-6)^2 - (7y)^2\]

\[\Large ({\color{red}{x-6}})^2 - ({\color{blue}{7y}})^2\]

\[\Large ({\color{red}{a}})^2 - ({\color{blue}{b}})^2 = ({\color{red}{a}}-{\color{blue}{b}})({\color{red}{a}}+{\color{blue}{b}})\]

Answer 6

\[\Large x^2 - 12x + 36 = (x-6)^2\]

\[\Large 49y^2 = (7y)^2\]

Answer 7

Would that be all?

Answer 8

no there's one more step

Answer 9

Hit me :)

Answer 10

use the difference of squares rule to factor

\[\Large (x-6)^2 - (7y)^2\]

Answer 11

(x-6)^2=x^-12x-36 right?
(7y)^2=49y^2 right?

Answer 12

you're going backwards though

Answer 13

what I'm aiming for is to go from this

\[\Large ({\color{red}{x-6}})^2 - ({\color{blue}{7y}})^2\]

to this

\[\Large ({\color{red}{x-6}}-{\color{blue}{7y}})({\color{red}{x-6}}+{\color{blue}{7y}})\]

I used the difference of squares rule

Answer 14

it's like saying x^2 - 64 factors to (x-8)(x+8)

Answer 15

Oh!! I get it now haha :D Thank you!

Answer 16

np