Question

Need help!

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A circle is centered at (−3, 2) and has a radius of 2. Which of the following is the equation for this circle?

(x + 3)2 + (y − 2)2 = 2
(x − 3)2 + (y + 2)2 = 4
(x + 3)2 + (y − 2)2 = 4
(x − 3)2 + (y + 2)2 = 2

Answer 1

@prowrestler @keshaun455 @mathstudent55 @itsmichelle29 @lizzieeej @vlz6000 @campbell_st

Answer 2

well the general form of a circle is

\[(x - h)^2 + (y - k)^2 = r^2\]

the centre is (h, k) and r is the radius

so substitute your information and get a solution.

Answer 3

What numbers exactly would i be substituting @campbell_st

Answer 4

well you are told the centre is (-3, 2) and radius is 2

so h = -3 k = 2 and r = 2

Answer 5

soo (x-3)2+ (y-2)2=4? @campbell_st

Answer 6

no

(x - (-3))^2 + (y -2)^2 = 2^2

simplify the 1st term

Answer 7

What 1st term?? I'm so confused @campbell_st

Answer 8

Would the answer be B then?

Answer 9

@k_lynn @campbell_st

Answer 10

the answer isn't B.. just substitute correctly

h = - 3

so (x - h) = ( x -(-3) which becomes (x + 3)