If sine of x equals 1 over 2, what is cos(x) and tan(x)? Explain your steps in complete sentences.
Hint: Pythagorean Trig Identity \[\Large \sin^2(x) + \cos^2(x) = 1\]
Ok, so how would I continue off that? May you guide me through the problem please?
since sine is 1/2, squaring that gives you 1/4 you can replace all of sin^2 with 1/4 like this \[\Large \sin^2(x) + \cos^2(x) = 1\] \[\Large \frac{1}{4} + \cos^2(x) = 1\]
now isolate cos(x)
we subract 1/4 from both sides
so now we square root both sides right?
correct on both statements
then how do we get tangent
\[\Large \tan(x) = \frac{\sin(x)}{\cos(x)}\]
Ok, hold on. Let me put everything together.
cos(x) = \[\sqrt{.75}\] is that how it should be written
or \[\Large \sqrt{\frac{3}{4}} = \frac{\sqrt{3}}{\sqrt{4}} = \frac{\sqrt{3}}{2}\]
most books I've seen use \[\Large \frac{\sqrt{3}}{2}\]
oh ok, so \[\tan(x) = \frac{ 1 }{ 2 } /\frac{ \sqrt{3} }{ 2 }\]
Yes correct. Now simplify
How would I do that?
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