Write the standard form of the equation of the line described. #1) through: (-5,3), perpendicular to y=5/7x+4.
do you know what the slope of \[\huge y=\color{red}{\frac{5}{7}}x+4\] is ?
5/7
ok good so the perpendicular line will have slope ?
5/7
no, that would be the slope of any parallel line you are asked for a perpendicular line
what would it be?
in english (math english) it is the "negative reciprocal" i.e. flip it and change the sign
-7/5
right
now use the point slope formula to find the equation, since you have a point and the slope
y=-7/5x-5, is this the correct answer?
i doubt it, since it has all those fractions
\[y-3=-\frac{7}{5}(x+5)\] is a start
multiply out and get \[y-3=-\frac{7}{5}x-7\] oh look the fractions are gone, but now you add \(3\) to both sides
y=-7/5x-4
looks good to me
My textbook said the answer would be 7x+5y=-20
that is because your text had you answer in standard from rather than point slope form
the question asked for standard form
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