rationalize the denominator and simplify (2√7+3)/(√7+2)
When you want to rationalize the denominator you want to multiply it by the numerator and denominator by the conjugate \[\sqrt{7}-2\]
\[\frac{ (2\sqrt{7}+3 )}{ (\sqrt{7}+2 )} \times \frac{ \sqrt{7}-2 }{ \sqrt{7}-2 }\]
why is it negative? shouldnt it be positive 2?
oh opps just kidding the bottom cancels out
To rationalize we use the conjugate which simply means we change the sign so notice how we want to rationalize the denominator so we multiply the top and bottom by sqrt(7)-2 we change the + to - this way we can get an expression as such \[a^2-b^2\]
Yeah!
"When you want to rationalize the denominator you want to multiply it by the numerator and denominator by the conjugate " signs need to be switched.. since you have a + on the denominator we have to multiply by sqrt{7}-2
ahaha I understand now! thank you both!
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