A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?

1 over 4096
1 over 512
1 over 64
1 over 8

Question

A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?

 1 over 4096
 1 over 512
 1 over 64
 1 over 8

misty1212 · Answer

she puts them back each time right?

anonymous · Answer

yes

misty1212 · Answer

and the beads are all different colors, so 8 different colors
the probability of any one color is therefore $\frac{1}{8}$

misty1212 · Answer

that is not the final answer though

anonymous · Answer

oh ok

misty1212 · Answer

do it 3 times in a row, the probability of red, white,  red is$$\frac{1}{8}\times \frac{1}{8}\times \frac{1}{8}$$

misty1212 · Answer

use a calculator to compute $$8^3$$ then put it in the denominator

anonymous · Answer

ok...i got 512 when i multiplied that so now what? @misty1212

anonymous · Answer

oh so is my answer  1/512 @misty1212

misty1212 · Answer

yes dear that is right

anonymous · Answer

thank you! ^_^