The prices of some jewelry sets in a store are shown below:

Store Price
A $110,000
B $100,000
C $1,110,000
D $130,000
E $120,000

Based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store?
Mean, because it is in the center of the data
Median, because it is in the center of the data
Median, because there is an outlier that affects the mean
Mean, because there are no outliers that affect the mean

Question

The prices of some jewelry sets in a store are shown below:


Store	Price
A	$110,000
B	$100,000
C	$1,110,000
D	$130,000
E	$120,000


Based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store?
 Mean, because it is in the center of the data
 Median, because it is in the center of the data
 Median, because there is an outlier that affects the mean
 Mean, because there are no outliers that affect the mean

anonymous · Answer

@mathstudent55

anonymous · Answer

There's outlier in your data set

iyuko · Answer

How does the book tell you to do this?

anonymous · Answer

there is no book

iyuko · Answer

the lesson

anonymous · Answer

mean is skewed by the outlier in the data set

iyuko · Answer

Show me the work @Kim21

iyuko · Answer

I will tell you if it's right.

anonymous · Answer

but i dont know how to do this :(

anonymous · Answer

yup no direct answer!

iyuko · Answer

You need to review

iyuko · Answer

What test is this?

anonymous · Answer

think back whats mean and median

anonymous · Answer

its a pretest so its just to see what i know so i haven't learned this yet but i want to still get the right answer cause it counts towards grade ;b

anonymous · Answer

median is the middle number of the data set and mean is when u add and divide the numbers in the data set

anonymous · Answer

The mean is the average of the numbers.

anonymous · Answer

yes so mean is$$Mean = \frac{ x_1 + x_2 +...+ x_n }{ n } $$

anonymous · Answer

what do you think happens if 1 of the x  is a huge number

anonymous · Answer

not sure :?

anonymous · Answer

the means becomes skewed by that large x

anonymous · Answer

@mathstudent55

anonymous · Answer

you made any progress so far?

anonymous · Answer

no im gonna call @mathstudent55 for some help but thanks anways :)

anonymous · Answer

read this http://www.quickmba.com/stats/centralten/

anonymous · Answer

you might find your answer there

anonymous · Answer

ok thanks! :)

mathstudent55 · Answer

An outlier affects more the mean that the median.
When you have outliers, using the median instead of the mean may give you a better picture of how the data is distributed.

mathstudent55 · Answer

See the great explanation here: https://www.mathsisfun.com/data/outliers.html