Question

What is the missing exponent?

Answer 1

Ok, we still work in the correct order of operations. In other words, let's work with the denominator first.\[\left(8^{-7}\right)^2 = 8^{-7}\times8^{-7}\]Here, you are multiplying, so what should that simplify to? (aka \(8^{??}\))

Answer 2

8^0???

Answer 3

When you multiply, you add the exponents. You would get \(8^0\) if you subtracted them.

Answer 4

oh ok so its 8^-14

Answer 5

Yes. So, plugging that in again, \[\frac{8^{-5}}{8^{-14}} = 8^{?}\] We are dividing here.

Answer 6

dividing which ones

Answer 7

(im putting my baby bro. to sleep right now so i might type slow i only have 1 hand)

Answer 8

1 hand free*

Answer 9

(That's fine.) You're dividing in general, so you're going to have to either add or subtract the exponents. When you multiply, you added, so when you divide, you...?

Answer 10

subtract

Answer 11

so 8^9

Answer 12

9 is the answer?

Answer 13

Yes! Also, just in general, the only time you will multiply exponents (with the same bases, like here where you had 8 on the bottom) is when you have something like \(\left(8^3\right)^2\). This would simplify to \(8^6\) because what you're doing is \(8^3 \times8^3\).

Answer 14

ok tysm! You're so smart :D

Answer 15

So, for you to write down, you can say \(\left(a^b\right)^c = a^{bc}\)

Answer 16

i did

Answer 17

I GOT A 100!!!!!!!!!!

Answer 18

Good job!! :)

Answer 19

tysm!!! i gtg bye

Answer 20

np