Question

I need help with some algebra homework. It is simplifying expressions with exponents. Please help!!

Answer 1

\[-2n ^{4} (12n ^{-7})\]

Answer 2

@Hero

Answer 3

@pooja195

Answer 4

@dan815

Answer 5

@amistre64

Answer 6

Multiply the coefficients and add the exponents
\[-2n^4(12n^-7)=(-2 \times 12)n^{4+(-7)}\]

Answer 7

but i need to simplify it.

example: \[-3n ^{2} (8n ^{-5}) =\frac{ -24 }{ n ^{3} } \]

Answer 8

I'm having trouble understanding the whole steps...

Answer 9

-24/n³ is simplifed

Answer 10

To multiply expressions when the bases are the same, add the exponents and multiply the coefficients
\[(-3n^2)(8n^{-5})=(-3 \times 8)n^{2+(-5)}=-24n^{-3}\]
For negative exponents, if you take the reciprocal of the base, you can make the exponent positive
Rule: \[x^{-m}=\left( \frac{ 1 }{ x } \right)^m\]
That's why the -3 became 3 and the n moved to the denominator
\[-24n^{-3}=-24\left( \frac{ 1 }{ n } \right)^3=\frac{ -24 }{ n^3 }\]

Answer 11

That was exactly what my teacher was trying to show us. It's just I was having trouble. Thanks for the help! :)

Answer 12

you're welcome