Question

HELP!!! I WILL DO ANYTHING

Answer 1

The function H(t) = -16t2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second.

Part A: The projectile was launched from a height of 82 feet with an initial velocity of 60 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points)

Part B: What is the maximum height that the projectile will reach? Show your work. (2 points)

Part C: Another object moves in the air along the path of g(t) = 10 + 63.8t where g(t) is the height, in feet, of the object from the ground at time t seconds.

Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points)

Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know? (2 points)

Answer 2

@dan815

Answer 3

@triciaal

Answer 4

A:0=-16t2+60t+82

Answer 5

YEAH, I have that part. but what do you mean by A;0 .. I have the numbers plugged in .. just solving is difficult

Answer 6

@jim_thompson5910

Answer 7

A: 0. Sry. Forgot the space

Answer 8

Just sayin for problem a.

Answer 9

either way what do you mean??

Answer 10

ohh

Answer 11

hello?

Answer 12

The equation for problem a is 0=-16t2+60t+82

Answer 13

I know that

Answer 14

part A is definitely 0 = -16t^2+60t+82. So you have the correct answer there for that part.

initial velocity = 60 ft/s
v = 60

initial height = 82 ft
s = 82

Answer 15

for part b, consider the equation y = -16x^2+60x+82

it is in the form y = ax^2 + bx + c

Answer 16

okay...
now what do i do?

Answer 17

yes

Answer 18

notice how a = -16, b = 60, c = 82

plug the values of a and b into h = -b/(2a) and tell me what you get for h

Answer 19

-1.875

Answer 20

it should be positive

Answer 21

you lost a sign somewhere

Answer 22

yea. it is . i accidentally put it there

Answer 23

now plug x = 1.875 into y = -16x^2+60x+82 to get the value of y

what is the value of y?

Answer 24

y=1094.5 ?

Answer 25

that's too big

Answer 26

,,,,, but i plugged the number in and I'm sure i solved it correctly..

Answer 27

-16x^2+60x+82

-16(1.875)^2+60(1.875)+82 ... replace every x with 1.875

now compute `-16(1.875)^2+60(1.875)+82`

Answer 28

yeah.. thats what i had. .let me retry

Answer 29

138.25??

Answer 30

much better

Answer 31

okay great.. next step?

Answer 32

For c, u make the equation in a equal 10 +63.8t
10+63.8t=-16t2+60t+82
In which you solve for t, then plug it in in one of the equations

Answer 33

HUH
^^^^

Answer 34

So when the time is t = 1.875 seconds, the height of the object is 138.25 ft which is the peak height