Open Solution Problem;Soft snow can be compressed by pressure about 3.0 ×10^3 Pa. What is the smallest area that a pair of snowshoes must have if they will enable a 80 kg person to walk over the snow without sinking in? Consider g = 9.8 m/s2.

Question

anonymous · Answer

The first person who gets it earns a medal and fan

anonymous · Answer

First you have to consider the ?Newtonian force acting on the ground. This is caculated using Mg

anonymous · Answer

And use the equation Pressure=F/A(surface area in m^2) with inequality equation

ddcamp · Answer

First find the force the person will exert on the snow, using Newton's 2nd law:
$$F = ma \ F = 88kg * 9.8 \frac{m}{s^2}$$

anonymous · Answer

Correct! Newton's second law or simply mass*gravityt

anonymous · Answer

In fact you are calculating the normal force using that equation above

ddcamp · Answer

Use the equation for pressure:$$P = F/A \ 3000 Pa = 862.4 N / A \ A = 862.4N / 3000 Pa \ A = 0.287 m^2$$

anonymous · Answer

Well done.