The graph of f(x) consists of 14 points. Six of the points lie in Quadrant I of the coordinate plane. If f(x) is an odd function, what is the greatest number of points that can lie in Quadrant II?
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Vocaloid (vocaloid):
hint:
f(x) is odd, so #of points in Q1 = #of points in Q3
Vocaloid (vocaloid):
6 points in Q1 = 6 points in Q3
this gives us 6+6 = 12 points not in Q2
so if there are 14 points total, how many can be in Q2?
OpenStudy (warpedkitten):
6?
OpenStudy (misty1212):
HI!
OpenStudy (misty1212):
if six are in quadrant 1, and it is odd, then 6 are in quadrant 3 right?
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OpenStudy (misty1212):
that leaves \(14-6=8\) to split between quadrant 2 and 4
OpenStudy (misty1212):
if it is odd, however many you see in quadrant 2, you see in quadrant 4 so halve of the remaining 8
OpenStudy (misty1212):
*half
OpenStudy (warpedkitten):
So 4?
OpenStudy (misty1212):
that is what i get, yes
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OpenStudy (misty1212):
say for example \((-2,3)\) is a point in quadrant 2 on the graph
then since \(f\) is odd, that means \((2,-3)\) is also on the graph, and that is in quadrant 4