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Mathematics 9 Online
OpenStudy (warpedkitten):

The graph of f(x) consists of 14 points. Six of the points lie in Quadrant I of the coordinate plane. If f(x) is an odd function, what is the greatest number of points that can lie in Quadrant II?

Vocaloid (vocaloid):

hint: f(x) is odd, so #of points in Q1 = #of points in Q3

Vocaloid (vocaloid):

6 points in Q1 = 6 points in Q3 this gives us 6+6 = 12 points not in Q2 so if there are 14 points total, how many can be in Q2?

OpenStudy (warpedkitten):

6?

OpenStudy (misty1212):

HI!

OpenStudy (misty1212):

if six are in quadrant 1, and it is odd, then 6 are in quadrant 3 right?

OpenStudy (misty1212):

that leaves \(14-6=8\) to split between quadrant 2 and 4

OpenStudy (misty1212):

if it is odd, however many you see in quadrant 2, you see in quadrant 4 so halve of the remaining 8

OpenStudy (misty1212):

*half

OpenStudy (warpedkitten):

So 4?

OpenStudy (misty1212):

that is what i get, yes

OpenStudy (misty1212):

say for example \((-2,3)\) is a point in quadrant 2 on the graph then since \(f\) is odd, that means \((2,-3)\) is also on the graph, and that is in quadrant 4

OpenStudy (warpedkitten):

Thank you. :)

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