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Mathematics
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OpenStudy (0_0youscareme):
l2a+1l=1
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OpenStudy (anonymous):
that is better
this is an absolute value equation so it requires solving two separate equations
OpenStudy (anonymous):
one is just what you see as if the absolute value signs are not there \[2a+1=1\] which you can solve in two easy steps
OpenStudy (anonymous):
the other is what you get when you change the sign of the number on the right, i.e \[2a+1=-1\] again two easy steps to solve
OpenStudy (0_0youscareme):
so you pretend the absolute value sign is not there?
OpenStudy (anonymous):
for one of them yes, but you have to solve two all together
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OpenStudy (anonymous):
so lets go ahead and solve them
start with \[2a+1=1\] and subtract 1 from both sides, what do you get?
OpenStudy (0_0youscareme):
you get 2a=0
OpenStudy (anonymous):
right
which means \(a=?\)
OpenStudy (0_0youscareme):
0?
OpenStudy (anonymous):
yes !
now on to the next equation
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OpenStudy (anonymous):
the next one is \[2a+1=-1\] again subtract 1, what do you get?
OpenStudy (0_0youscareme):
2a=-2
OpenStudy (anonymous):
right, and now divide by 2
OpenStudy (0_0youscareme):
A=-1
OpenStudy (anonymous):
yes
lets recap
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OpenStudy (anonymous):
if you have an absolute value equation like \[|2x+3|=5\] you have to solve two equations:\[2x+3=5\] and also \[2x+3=-5\]
OpenStudy (0_0youscareme):
so on a graph it would look like |dw:1439951388453:dw|
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