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Mathematics 8 Online
OpenStudy (0_0youscareme):

l2a+1l=1

OpenStudy (anonymous):

that is better this is an absolute value equation so it requires solving two separate equations

OpenStudy (anonymous):

one is just what you see as if the absolute value signs are not there \[2a+1=1\] which you can solve in two easy steps

OpenStudy (anonymous):

the other is what you get when you change the sign of the number on the right, i.e \[2a+1=-1\] again two easy steps to solve

OpenStudy (0_0youscareme):

so you pretend the absolute value sign is not there?

OpenStudy (anonymous):

for one of them yes, but you have to solve two all together

OpenStudy (anonymous):

so lets go ahead and solve them start with \[2a+1=1\] and subtract 1 from both sides, what do you get?

OpenStudy (0_0youscareme):

you get 2a=0

OpenStudy (anonymous):

right which means \(a=?\)

OpenStudy (0_0youscareme):

0?

OpenStudy (anonymous):

yes ! now on to the next equation

OpenStudy (anonymous):

the next one is \[2a+1=-1\] again subtract 1, what do you get?

OpenStudy (0_0youscareme):

2a=-2

OpenStudy (anonymous):

right, and now divide by 2

OpenStudy (0_0youscareme):

A=-1

OpenStudy (anonymous):

yes lets recap

OpenStudy (anonymous):

if you have an absolute value equation like \[|2x+3|=5\] you have to solve two equations:\[2x+3=5\] and also \[2x+3=-5\]

OpenStudy (0_0youscareme):

so on a graph it would look like |dw:1439951388453:dw|

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