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Chemistry 11 Online
OpenStudy (anonymous):

you wanted a 1.8 M of KMNO4 and we know that the molecular weight of KMno4 is 158 g/mole how can we make the solution?

OpenStudy (taramgrant0543664):

v=m/c Where m is mass you can put that as 158g/mol possibly c is concentration so the 1.8M v is volume I don't know if this would work though sorry!

OpenStudy (anonymous):

I will try to answer it the way you explained it, thanks a lot though!

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