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Mathematics 19 Online
OpenStudy (anonymous):

.

OpenStudy (misty1212):

you do not need to graph this to do it

OpenStudy (misty1212):

put in the number for x, see if you get the y

OpenStudy (anonymous):

Oh really okay

OpenStudy (misty1212):

you are right however

OpenStudy (misty1212):

it is \[f(x)=\sqrt{x+6}+2\]right?

OpenStudy (anonymous):

yeah

OpenStudy (misty1212):

so \[f(-2)=\sqrt{-2+6}+2=\sqrt{4}+2=2+2=4\]

OpenStudy (misty1212):

i.e if \(x=-2\) then \(y=4\) so \((-2,4)\) is on the graph

OpenStudy (anonymous):

oh I was right then? I was dying trying to graph this because it wasn't really exact but (-2, 4) was the closest.

OpenStudy (anonymous):

I like your way better.

OpenStudy (misty1212):

how did you graph it?q

OpenStudy (anonymous):

It's on paper so I can only describe it but it was exactly on the -4 just a little under.

OpenStudy (anonymous):

Your way gives me the exact thing though so that's nice.

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