how does csc(-120) equal to -csc(120)?
sin and tan are odd cos = even \[\large\rm sin(-\theta)= -\sin \theta\]\[\large\rm cos(-\theta)= \cos \theta\]\[\large\rm Tan(-\theta)= - Tan \theta\]
I still don't understand
what is reciprocal of sin ,cos and tan ???
Honestly I have no idea. I am the worst with trigonometry. I don't understand it whatsoever
then u need to start it over \[\large\rm sin =\frac{ 1 }{ \csc }~~\cos=\frac{ 1 }{ \sec }~~~\tan=\frac{ 1 }{ \cot }=(\frac{ \sin }{ \cos })\] reciprocal of sin is 1/csc reciprocal of cos is 1/sec reciprocal of tan is 1/cost or you can say sin /cos csc=1/sin sec=1/cos cot=1/tan csc , sec and cot are reciprocal of sin , cos and tan
if sin =a/b then csc = b/a
so if sin is odd function then csc is odd or even ?
odd
yes right that's how \[\huge\rm csc(-120)= - \csc(120)\]
another way of looking at it is using the unit circle and fact that neg angle goes clock-wise |dw:1440006652430:dw|
but I'm just not understanding how the negative comes out
sin refers to "y-value" , on the circle sin(-120) is the neg y-value of sin(120)
|dw:1440007033356:dw|
Join our real-time social learning platform and learn together with your friends!