Question

How do I calculate the absolute uncertainty when there is an exponent? (see question 2)

Answer 1

1) when the number is
(5.3322∗ 10^-5) would the uncertainty be (1*10^-9) or (0.0001)?

Answer 2

2) how to calculate the absolute uncertainty when there is an exponent? For example \[(-7.5899*10^{-6}) *(22.62 \pm 0.01) \].

Answer 3

for example lets say u are given
10.1 you dont know if it was
10.05 to 10.15
so your uncertainty is
10.1 +/- 0.05

Answer 4

We were told in class that when the uncertainty is implicit we will assume its the last digit and it will always be 1. For example: 0.0967 the uncertainty will be 0.0001.

Answer 5

(5.3322∗ 10^-5)
same thing this part
5.3322 you dont know if it was 5.33215 to 5.33225
so 5.3322 +/- 0.00005

Answer 6

ok i guess that maybe fine too its like roudning up the uncertainty itself

Answer 7

+/- 0.00005 = +/- 0.0001

Answer 8

ooohhhh ok. so the uncertainty will be determined regardless of the exponent.

Answer 9

yeah that is right

Answer 10

(5.33220∗ 10^-5) if they want to go upto exponent

Answer 11

you have to add that 0

Answer 12

ok. thanks!!

Answer 13

sure np

Answer 14

for your question 2, absolute uncertainty is that the uncertainty that is based on proportion

Answer 15

iwhen y=x^n,
is the formula n* (relative uncertainty),
relative uncertainty= (uncertainty/value)

Answer 16

okay i see

Answer 17

here is a more logical approach to calculating your absolute uncertainty

Answer 18

suppose you have
10.0+/- 0.1 and 2.0+/- 0.2
you see
10.0*2.0 = 20.0
then you see the max and mix that happens with the uncertainty
10.1*2.2 = 20.2 + 2.02 = 22.22
and the min
9.9*1.8 = 18-0.18=17.82

Answer 19

(22.22-17.82)/2 would be the uncertainty?

Answer 20

ok

Answer 21

let me check how u actually find absolute uncertainties hmm

Answer 22

look at this
http://web.uvic.ca/~jalexndr/192UncertRules.pdf

Answer 23

that is probably best forget what i said so far

Answer 24

ok. thank you so much!!