Question

.

Answer 1

is it

\[\Large \sqrt{x-1}\]

OR

is it

\[\Large \sqrt{x}-1\]

??

Answer 2

it is the first one the line covers both the x and 1

Answer 3

i just didn't know how to show that on here

Answer 4

that's ok. thanks for clarifying

Answer 5

yw

Answer 6

so the basic rule is that if you have some function f(x), if you replaced x with x-h then the entire graph shifts h units to the right (if h is positive)

for example

\[\Large f(x) = \sqrt{x}\]

\[\Large f(\color{red}{x}) = \sqrt{\color{red}{x}}\]

\[\Large f(\color{red}{x-7}) = \sqrt{\color{red}{x-7}} \ \text{shift 7 units right}\]

Answer 7

in this case it would shift one unit to the right?

Answer 8

if h was negative, then the shift would go left

eg:

\[\Large f(x) = \sqrt{x}\]

\[\Large f(\color{red}{x}) = \sqrt{\color{red}{x}}\]

\[\Large f(\color{red}{x-(-12)}) = \sqrt{\color{red}{x-(-12)}} \ \text{shift 12 units left}\]

\[\Large f(\color{red}{x+12}) = \sqrt{\color{red}{x+12}} \ \text{shift 12 units left}\]

Answer 9

correct, in this problem, the `x-1` under the root means "shift the parent graph 1 unit to the right"

Answer 10

I recommend you compare the two graphs using something like desmos

https://www.desmos.com/calculator

Answer 11

so I was right then

Answer 12

@jim_thompson5910 thanks for going over that with me. It's appreciated :)

Answer 13

you're welcome

Answer 14

@jim_thompson5910 I have another question, if it said x+7 (kinda like what you wrote but addition) would it be like shift the unites to the left?

Answer 15

yep the `x+7` under the root would mean "shift 7 units left"

Answer 16

okay cool. I get these now, thank you. And thanks for the graph website :D

Answer 17

sure thing. I'm glad to be of help