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Mathematics 14 Online
OpenStudy (anonymous):

what part of the graph of f'(x) determines the inflection points of f(x)???

OpenStudy (anonymous):

|dw:1440028143297:dw|

OpenStudy (anonymous):

To find the inflection point you find the 2nd derivative of f(x) and then find x ( f''(x)=0 )

OpenStudy (anonymous):

okay so the x intercepts of f'(x) are the inflection points on f(x) right?

jimthompson5910 (jim_thompson5910):

The extrema of f ' (x) have the same x coordinates of the roots of f '' (x), which is also where the inflection points on f(x) have the same x coordinates

jimthompson5910 (jim_thompson5910):

`okay so the x intercepts of f'(x) are the inflection points on f(x) right?` incorrect

OpenStudy (anonymous):

okay i think i understand , where the tangent is zero on the graph of f'(x) is where f(s) has an inflection point

jimthompson5910 (jim_thompson5910):

sorta, it has to be an extrema

jimthompson5910 (jim_thompson5910):

the tangent slopes have to change from positive to negative, or vice versa

OpenStudy (anonymous):

what do you mean by extrema ?

jimthompson5910 (jim_thompson5910):

let's say we had this f ' (x) graph |dw:1440028912113:dw|

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