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what is the inverse of the function y=5x^3?
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To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)
\[y=5x^3 \implies x = 5y^3\] solve for y now
so would it y=5x/3?
No where did you get the 3
\[y^3 = \frac{ x }{ 5 }\] you will have to take the cube root not divide by 3.
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\[\huge x^{1/3} = \sqrt[3]{x}\] cube root
\[\sqrt[3]{5x}\]
so it would be that ^ correct?
Nope, you take the cube root of both sides, \[\huge y^3 = \frac{ x }{ 5 } \implies y = \sqrt[3]{\frac{ x }{ 5 }} \implies f^{-1}(x) = \sqrt[3]{\frac{ x }{ 5 }}\]
\[\large y^3 = \frac{ x }{ 5 } \implies y = \sqrt[3]{\frac{ x }{ 5 }} \implies f^{-1}(x) = \sqrt[3]{\frac{ x }{ 5 }}\]
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thank you !!
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