Question

A Web music store offers two versions of a popular song. The size of the standard version is
2.7 megabytes (MB). The size of the high-quality version is 4.6 MB. Yesterday, the high-quality version was downloaded twice as often as the standard version. The total size downloaded for the two versions was 2499 MB. How many downloads of the standard version were there?

@Vocaloid

Answer 1

well, this is a very similar problem to the other one, so let's start off the same way.

H = number of high-quality downloads
S = number of standard-quality downloads

H = 2*S
2.7*S + 4.6*H = 2499

do you think you can finish from here? if you get stuck, remember the other problem that we just did

Answer 2

I don't have the other problem since it got rid of it so do I take 2.7(3-S)+4.6=2499?

Answer 3

I'm not sure where you're getting 3 from

Answer 4

i mean 2 sorry

Answer 5

remember,

H = 2*S

means that you can replace "H" with "2S" whenever you see it

Answer 6

take another look if you are still confused

http://openstudy.com/study#/updates/55d52a97e4b0554d6272fa4c

Answer 7

so2.7s+4.6(2-s)=2499?

Answer 8

almost, there shouldn't be a minus sign...

2.7S + 4.6(2*S) = 2499, agreed?

Answer 9

alright so if im correct i'd take 4.6 and times it by 2?

Answer 10

right, and that gives us...?

Answer 11

9.2?

Answer 12

don't forget the S

4.2(2*S) = 9.2S

Answer 13

so that leaves us with

2.7*S + 9.2*S = 2499

can you try solving for S now?

Answer 14

would it be 210?

Answer 15

yup, so that's our answer

Answer 16

thank you

Answer 17

S = number of standard downloads = 210