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OpenStudy (anonymous):
U dont need help
OpenStudy (anonymous):
OpenStudy (anonymous):
Tht shii confusing oml
OpenStudy (anonymous):
lol fr
OpenStudy (anonymous):
ima ask my cousin xD
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OpenStudy (anonymous):
lol who dat
OpenStudy (anonymous):
He in 11th
OpenStudy (anonymous):
Ok kewl
OpenStudy (anonymous):
he said he dont know either
OpenStudy (anonymous):
ok lol
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OpenStudy (campbell_st):
on... so Gary has 10 of 50 tickets
so the P(Gary WIn) = 10/50
so if he wins 1st prize, how many tickets does he still have and how many tickets are still in the draw..?
OpenStudy (campbell_st):
The problem is simply a case of
P(win, Win) = P(win1st) x P(win 2nd)
OpenStudy (anonymous):
ummmmm lol idk dang bruuuh thiis stuuf dawg on HARD!!!
OpenStudy (campbell_st):
so any ideas on how many tickets you have in the 2nd draw..?
and how many tickets are left in the draw...?
OpenStudy (anonymous):
so ima take a wild guest and say 50 again ?????
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OpenStudy (campbell_st):
great... so how many tickets does Gary have in the draw for the 2nd prize..?
OpenStudy (anonymous):
uhhhhhh 40 my brothua lol
OpenStudy (campbell_st):
no wonder you're tired, that is not even close..
OpenStudy (anonymous):
LOL!!!
OpenStudy (anonymous):
@campbell_st HELPPPPP
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OpenStudy (campbell_st):
so Gary has 10 tickets.... is that ok..?
OpenStudy (anonymous):
yeah
OpenStudy (campbell_st):
P(1st Prize) = 10/50 or 1/5
P(2nd Prize) = 10/50 or 1/5
P(1st, 2nd) = 1/5 * 1/5
OpenStudy (anonymous):
ok what i do next
OpenStudy (anonymous):
@campbell_st
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OpenStudy (campbell_st):
just multiply the fractions \[P(1st, 2nd) = \frac{1}{5} \times \frac{1}{5}\]
OpenStudy (anonymous):
and then i find tha percent and go my butt to bed lol
OpenStudy (campbell_st):
exactly
OpenStudy (anonymous):
Ok im gonna do that then u can see if im right plz
OpenStudy (anonymous):
@campbell_st i got 1 over 25 =1/25
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