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Mathematics 17 Online
OpenStudy (anonymous):

HELP !!!! im soo tired

OpenStudy (anonymous):

U dont need help

OpenStudy (anonymous):

OpenStudy (anonymous):

Tht shii confusing oml

OpenStudy (anonymous):

lol fr

OpenStudy (anonymous):

ima ask my cousin xD

OpenStudy (anonymous):

lol who dat

OpenStudy (anonymous):

He in 11th

OpenStudy (anonymous):

Ok kewl

OpenStudy (anonymous):

he said he dont know either

OpenStudy (anonymous):

ok lol

OpenStudy (campbell_st):

on... so Gary has 10 of 50 tickets so the P(Gary WIn) = 10/50 so if he wins 1st prize, how many tickets does he still have and how many tickets are still in the draw..?

OpenStudy (campbell_st):

The problem is simply a case of P(win, Win) = P(win1st) x P(win 2nd)

OpenStudy (anonymous):

ummmmm lol idk dang bruuuh thiis stuuf dawg on HARD!!!

OpenStudy (campbell_st):

so any ideas on how many tickets you have in the 2nd draw..? and how many tickets are left in the draw...?

OpenStudy (anonymous):

so ima take a wild guest and say 50 again ?????

OpenStudy (campbell_st):

great... so how many tickets does Gary have in the draw for the 2nd prize..?

OpenStudy (anonymous):

uhhhhhh 40 my brothua lol

OpenStudy (campbell_st):

no wonder you're tired, that is not even close..

OpenStudy (anonymous):

LOL!!!

OpenStudy (anonymous):

@campbell_st HELPPPPP

OpenStudy (campbell_st):

so Gary has 10 tickets.... is that ok..?

OpenStudy (anonymous):

yeah

OpenStudy (campbell_st):

P(1st Prize) = 10/50 or 1/5 P(2nd Prize) = 10/50 or 1/5 P(1st, 2nd) = 1/5 * 1/5

OpenStudy (anonymous):

ok what i do next

OpenStudy (anonymous):

@campbell_st

OpenStudy (campbell_st):

just multiply the fractions \[P(1st, 2nd) = \frac{1}{5} \times \frac{1}{5}\]

OpenStudy (anonymous):

and then i find tha percent and go my butt to bed lol

OpenStudy (campbell_st):

exactly

OpenStudy (anonymous):

Ok im gonna do that then u can see if im right plz

OpenStudy (anonymous):

@campbell_st i got 1 over 25 =1/25

OpenStudy (campbell_st):

correct as a fraction or 4%

OpenStudy (anonymous):

so is 0.04

OpenStudy (campbell_st):

correct...

OpenStudy (anonymous):

THANK CHU

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