Question

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Answer 1

their all negative options. I just didn't notice there weren't there sorry.

Answer 2

replaced x with -4

Answer 3

isn't it g(x)*f(x)*(-4)

Answer 4

are you familiar with these?

Answer 5

actually what i hav studied is that f(x) or g(x) can be written as f or g
and f'g is f multiplied g

Answer 6

I think there's a few ways you can actually do it.

Answer 7

there is also braces for (f'g) separating it from (-4)

Answer 8

@dan915 @amilapsn

Answer 9

those ways can change the entire ans. actually!

Answer 10

@nincompoop

Answer 11

yeah

Answer 12

Here's the question is \((g\circ f)(x)\) right?

Answer 13

yeah

Answer 14

Here's the thing:
\[(g\circ f)(x)=g\left( f(x)\right)\\
gf(x)=g(x)\times f(x) \]
right?

Answer 15

that circle between g and f means g "of" f

Answer 16

Still confused? It's the same as before g(f(4))

Answer 17

Same sort of question

Answer 18

I did

g(f(-4)) = 3(4x+7)-5


but that's wrong

Answer 19

so now I'm going through everything again

Answer 20

That's g(f(x)), you're on the right track g(x) = 3x-5 and f(x) = 4x+7

g(f(x)) = 3(4x+7)-5

for g(f(1)) we plug in 1 now where the x is. g(f(1)) = 3[4(1)+7]-5

Answer 21

oh I was doing -4 but I do 1 I guess.

Answer 22

Oh oops it's -4

Answer 23

oh

Answer 24

g(f(-4)) = 3[4(-4)+7]-5

Answer 25

You're doing it right then, why doubt yourself? :P

Answer 26

The other people helping me were showing me different things so I just assumed I was wrong. I was feeling really confident about it actually.

Anyways I was right and the answer is -32.

Answer 27

Yay :)

Answer 28

!!