Question

Someone Please help me regarding this question...I tried to prove it, but was not successful...

Answer 1

Please note that:

y1 = First Derivative
y2 = Second Derivative

Answer 2

What subject it is?

Answer 3

after differentiation
y1 =e^arctan(x)/(x^2 +1)

y2=[-e^arctan(x) (2x+1)]/(x^2 +1)^2

Answer 4

lets call e^arctan(x)=a

so we have
y1=a/(x^2 +1)

y2=[(-a)(2x+1)]/(x^2+1)^2

Answer 5

it would be long if we put the values of y1,y2 ad y in the equation so lets think of a shorter method...

Answer 6

I am so sorrry... Since I am at the office now.. wont be able to look at it... if you can suggest methods to solve it.. i can surely verify once I am home..

Answer 7

ok :)

Answer 8

and one thing... I tried many steps... lol

Answer 9

Is that even math............ I'm afraid of my future........

Answer 10

LOOOL XD

Answer 11

Also your very smart imqwerty considering I cant even read the problem right and your sitting here practically answering it

Answer 12

@midhun-madhu1987 We are in the same boat. I tried many ways, still not get the correct one. :)

Answer 13

@oldrin.bataku

Answer 14

@JoannaBlackwelder Could you have a look at it...

Answer 15

Sure, I'll give it a shot.

Answer 16

I get y2=[(-a)(2x-1)]/(x^2+1)^2
Is that what you get?

Answer 17

are you sure there's not a typo in the question?
https://gyazo.com/37935600cf0886aefbb297d1146e840c

Answer 18

Yeah, ditto. I get really close, but not all of the terms cancel.

Answer 19

The same happened to me too @JoannaBlackwelder