Counting Problem
\(\large \color{black}{\begin{align} & \normalsize \text{In how many ways can 4 boys & 4 girls be arranged}\hspace{.33em}\\~\\ & \normalsize \text{such that no 2 girls are together.}\hspace{.33em}\\~\\ \end{align}}\)
You can probably make an organized list, or sample space
ok
3 girls together also includes 2 girls together
u mean answer is 2
\(\large \color{black}{\begin{align} & \normalsize \text{In how many ways can 4 boys & 4 girls be arranged in a row}\hspace{.33em}\\~\\ & \normalsize \text{such that no 2 girls are together.}\hspace{.33em}\\~\\ \end{align}}\)
forget about girls, first you arrange the \(4\) boys
how many ways can you arrange \(4\) boys ?
4!=24
Yes |dw:1440079075919:dw|
don't mind me - I am not good with this stuff - just read/listen to what @ganeshie8 wrote
5*4=20
.
scratch that
have u also counted this situation gbbgbgbg
next, for each of that arrangement, the girls can only go between the boys. so there are exactly \(5\) for the \(4\) girls to go : |dw:1440079754229:dw|
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