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OpenStudy (mathmath333):
\(\large \color{black}{\begin{align}
& \normalsize \text{In how many ways can 4 boys & 4 girls be arranged}\hspace{.33em}\\~\\
& \normalsize \text{such that no 2 girls are together.}\hspace{.33em}\\~\\
\end{align}}\)
OpenStudy (anonymous):
You can probably make an organized list, or sample space
OpenStudy (mathmath333):
ok
OpenStudy (mathmath333):
3 girls together also includes 2 girls together
OpenStudy (mathmath333):
u mean answer is 2
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OpenStudy (mathmath333):
\(\large \color{black}{\begin{align}
& \normalsize \text{In how many ways can 4 boys & 4 girls be arranged in a row}\hspace{.33em}\\~\\
& \normalsize \text{such that no 2 girls are together.}\hspace{.33em}\\~\\
\end{align}}\)
ganeshie8 (ganeshie8):
forget about girls,
first you arrange the \(4\) boys
ganeshie8 (ganeshie8):
how many ways can you arrange \(4\) boys ?
OpenStudy (mathmath333):
4!=24
ganeshie8 (ganeshie8):
Yes
|dw:1440079075919:dw|
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OpenStudy (anonymous):
don't mind me - I am not good with this stuff - just read/listen to what @ganeshie8 wrote
OpenStudy (mathmath333):
5*4=20
OpenStudy (irishboy123):
.
ganeshie8 (ganeshie8):
scratch that
OpenStudy (mathmath333):
have u also counted this situation
gbbgbgbg
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ganeshie8 (ganeshie8):
next, for each of that arrangement,
the girls can only go between the boys.
so there are exactly \(5\) for the \(4\) girls to go :
|dw:1440079754229:dw|