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Mathematics 13 Online
OpenStudy (mathmath333):

Counting Problem

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align} & \normalsize \text{In how many ways can 4 boys & 4 girls be arranged}\hspace{.33em}\\~\\ & \normalsize \text{such that no 2 girls are together.}\hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (anonymous):

You can probably make an organized list, or sample space

OpenStudy (mathmath333):

ok

OpenStudy (mathmath333):

3 girls together also includes 2 girls together

OpenStudy (mathmath333):

u mean answer is 2

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align} & \normalsize \text{In how many ways can 4 boys & 4 girls be arranged in a row}\hspace{.33em}\\~\\ & \normalsize \text{such that no 2 girls are together.}\hspace{.33em}\\~\\ \end{align}}\)

ganeshie8 (ganeshie8):

forget about girls, first you arrange the \(4\) boys

ganeshie8 (ganeshie8):

how many ways can you arrange \(4\) boys ?

OpenStudy (mathmath333):

4!=24

ganeshie8 (ganeshie8):

Yes |dw:1440079075919:dw|

OpenStudy (anonymous):

don't mind me - I am not good with this stuff - just read/listen to what @ganeshie8 wrote

OpenStudy (mathmath333):

5*4=20

OpenStudy (irishboy123):

.

ganeshie8 (ganeshie8):

scratch that

OpenStudy (mathmath333):

have u also counted this situation gbbgbgbg

ganeshie8 (ganeshie8):

next, for each of that arrangement, the girls can only go between the boys. so there are exactly \(5\) for the \(4\) girls to go : |dw:1440079754229:dw|

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