MATHEMATICAL INDUCTION

Question

anonymous · Answer

$$1^{2}+4^{2}+7^{2}+....+(3n-2)^{2}=\frac{ n(6n ^{2}-3n-1) }{ 2 }$$

anonymous · Answer

How would I do s(k+1)? @ganeshie8

irishboy123 · Answer

see here http://openstudy.com/users/irishboy123#/updates/55d3474fe4b0554d62727bc4

anonymous · Answer

Okay thanks that shows me the work but I dont understand it, can you explain to me step by step? @IrishBoy123

irishboy123 · Answer

sure

in inductions, you first prove it is true for some value of n.  so establish that bit first.

anonymous · Answer

I already did that part: n=1 and n=k I just dont know how to d the n=k+1

anonymous · Answer

Honestly, I don't get it.

irishboy123 · Answer

OK, one important thing.  last time i helped on this the OP specified "for all positive integers n"  so yes you had to start with n = 1.  we will use induction to prove that it must therefore be true for n = 2, and thuse n = 3 and thus ....

so the next step is to assume it is true for n = k.  that means the following is assumed true

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