Sums of consecutive integers
The sum of 3 consecutive odd numbers is 117.What is the first number in this sequence?
31
@kaitlyn_nicole \(31+33+35=99\ne 117\) Perhaps a typo?
if I have 3 consecutive odd numbers, then they will be of the form n, n+2, n+4 we want to add them and get 117, so n+(n+2)+(n+4)=117
no no typo
he was not saying you have a typo @jamesr
o
but i dont understand this
its 37 sorry
ugh nvm
\[37+39+41=117\]
@kaitlyn_nicole Excellent, now can you explain to @jamesr how you got it so that he can solve similar problems?
you do n+(n+2)+(n+4) = 117 thats the equation, tbh i have a very weird way of doing things but i mainly predicted what n was and worked my way from there.
@kaitlyn_nicole I know your way, "guess and check", that's the fastest possible way, but does not work in all cases. We still have to know the proper way to do things to fall back on. Good job!
I think it's best to help with the set up, with lots of explanation, and let them finish.
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