Question

This is an algebra 2 question that requires some skill, but help would be greatly appreciated!

Answer 1

\[\frac{ x }{ (x-1)^{2} }+\frac{ 2 }{ x }-\frac{ x+1 }{ x ^{3}-x ^{2} }\]

Answer 2

Simplify please!

Answer 3

Looking for someone to walk you through it?

Answer 4

Well, actually jsut the answer to the simplified equation would be good enough!

Answer 5

that's why I asked. We're not allowed to give answers here as it doesn't really benefit anyone.
http://openstudy.com/code-of-conduct
If you just want the answer try an online calculator like wolframalpha.com

Answer 6

Well then please go ahead and walk me through, that would be still great.

Answer 7

I'll help you.

Answer 8

(x/x^2-1) + (2/x) + (x+1/x^3-x^2)
=(x^-1/-1) + (2/x) + (x^-4 +1)

Answer 9

=(x^-1/-1) + (2x^-1) + (x^-4 +1)

Answer 10

=(x^-1/-1) + 2x^-5 +1

Answer 11

Not sure what to do from there. It's been a couple years since I've done Algebra 2.

Answer 12

I'm sure there are laws that tell you what to do.

Answer 13

Factor the third denominator to get \[x^2(x-1)\]

Answer 14

So now the 3 denominators are
(x- 1)², x, and x²(x -1)

the least common denominator needs to have the maximum of each factor. So we need both x and (x -1) twice

LCD = \(x^2(x-1)^2\)

Answer 15

To make all 3 fraction match the LCD you have to multiply them by different factors.

Multiply the first by \[\frac{ x^2 }{ x^2 }\]
Multiply the 2nd by \[\frac{ x(x-1)^2 }{ x(x-1)^2 }\]
Multiply the 3rd by \[\frac{ x-1 }{ x-1 }\]

Answer 16

the problem is now\[\frac{ x(x^2) }{ x^2(x-1)^{2} }+\frac{ 2x(x-1) }{ x(x)(x-1) }-\frac{ (x+1)(x-1) }{ x^2(x-1)^2 }\]

Answer 17

\[\frac{ x^2+2x(x-1)-(x+1)(x-1) }{ x^2(x-1)^2 }\]

Simplify the numerator and see if anything cancels with the denominator after