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What is the missing exponent? (6 )-4 = 620
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(6 )^-4 = 620 (the negative 4 is an exponent)
so are you looking for the exponent of 6...? as in \[(6^x)^{-4} = 620\]
yes
@campbell_st
ok... so using the power of a power law which means multiply the powers \[6^{-4x} = 620\] now you need logs to solve it take the log of both sides \[\ln(6^{-4x}) = \ln(620)\] applying the log laws for powers \[-4x \times \ln(6) = \ln(620)\] so \[-4x = \frac{\ln(620)}{\ln(6)}\] now solve for x
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I'm still confused, how do I solve for x?
@campbell_st
so when you get a value for the log division, just divide it by -4
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