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Mathematics 20 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

im attaching picture now

OpenStudy (anonymous):

OpenStudy (anonymous):

16-20

Vocaloid (vocaloid):

well, ok, let's start with 16 16: JK look at the number line and tell me how many spaces are between J and K?

OpenStudy (anonymous):

3

Vocaloid (vocaloid):

right, so our answer is 3

OpenStudy (anonymous):

next one is 5?

Vocaloid (vocaloid):

not quite 1-(-6) = ?

OpenStudy (anonymous):

lol 7

Vocaloid (vocaloid):

good, next?

OpenStudy (anonymous):

12?

Vocaloid (vocaloid):

yup, next?

OpenStudy (anonymous):

9?

Vocaloid (vocaloid):

good. #20 is a bit trickier, allow me a moment to explain

OpenStudy (anonymous):

kk thx

Vocaloid (vocaloid):

the segment postulate theorem states that, if we have a segment like (using an example here) AC, with B in the middle, then AB + BC = AC

OpenStudy (anonymous):

i dont think it would be possible because they dont give us numbers

Vocaloid (vocaloid):

we know that FB = FC + CB, and if we assume that FC > 0, then FB > CB

Vocaloid (vocaloid):

however, I would agree with you, since we don't have numbers, we can't make any assumptions here

OpenStudy (anonymous):

so thats what i should say for explain?correct?

OpenStudy (anonymous):

THis is what i said...

OpenStudy (anonymous):

we cannot use the segment addition postulate because we are not given exact numbers to work with

Vocaloid (vocaloid):

well, I would say something like, "we can show that FB > CB since FB = CB + FC but we can't make any definitive statment for AC and DB since these segments overlap"

OpenStudy (anonymous):

k should i say something about the exact numbers or could i leave that out

Vocaloid (vocaloid):

sure, if you'd like

OpenStudy (anonymous):

k i have some more if you dont mind but i'll put it in a different question

Vocaloid (vocaloid):

sure

OpenStudy (anonymous):

@vocaloid

Vocaloid (vocaloid):

sure, post a new Q and tag me

OpenStudy (anonymous):

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