Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Vocaloid (vocaloid):
sure, looks ok to me
OpenStudy (anonymous):
could you help me on a couple more so sorry something happened at school and teacher didn't explain but im learning alot now
Vocaloid (vocaloid):
sure.
OpenStudy (anonymous):
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i only need help on 27
Vocaloid (vocaloid):
the diagram is a bit hard to read, can you tell me what the blue numbers are?
Vocaloid (vocaloid):
1.6x, x, and 6 ?
OpenStudy (anonymous):
lol yup
Vocaloid (vocaloid):
well, the segment postulate theorem tells us that
length of the whole segment = lengths of each smaller segment added together
1.6x = x + 6
start by subtracting x from each side, what do you get?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
1.6x-x=6?
Vocaloid (vocaloid):
right, keep going
1.6x - x = __x?
OpenStudy (anonymous):
um lol dk sorry
Vocaloid (vocaloid):
1.6 - 1 = 0.6
1.6x - x = ?
OpenStudy (anonymous):
.6x?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
Vocaloid (vocaloid):
right. now we have
0.6x = 6
divide both sides by 0.6, what do you get?
OpenStudy (anonymous):
10
Vocaloid (vocaloid):
riight, so x = 10
now, EG = 1.6*x = ?
OpenStudy (anonymous):
what i dont understand is i thought they give you the length of eg, because the 1.6x spans the whole length of the diargram
Vocaloid (vocaloid):
well, yes, EG is 1.6x, meaning 1.6 times x. HOWEVER, we need to figure out what x is first, by solving
1.6x = x + 0.6
does that make sense?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so x is 10
Vocaloid (vocaloid):
right, x = 10
now, we can use that to find EG
EG = 1.6*x = ?
OpenStudy (anonymous):
so its 16!
OpenStudy (anonymous):
right?
Vocaloid (vocaloid):
yup! excellent work
Still Need Help?
Join the QuestionCove community and study together with friends!