Question

Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

Make 6 squares. The squares are numbered sequentially from 1 to 6.

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered 3 from the second bag?

1 over 36
1 over 12
2 over 12
2 over 6

Answer 1

@Vocaloid

Answer 2

well, there are 6 tiles in each bag, numbered 1 through 6...

so what is the probability of getting tile #2 from the first bag?

Answer 3

2/6 ?

Answer 4

not quite... there is only 1 tile with number 2 on it, so...

1/6

Answer 5

now, the probability of getting the number 3 tile from the second bag is the same, 1/6

Answer 6

now we multiply them together...

(1/6)*(1/6) = ?

Answer 7

1/36 which is A?

Answer 8

Kim wants to arrange chocolate, vanilla, and pineapple cakes in a row on a shelf. Which tree diagram best shows the sample space of all the possible ways to arrange the three cakes in a row on a shelf, where C is chocolate, V is vanilla, and P is pineapple?

A tree diagram is shown. The lines branch out to C, P, and V. In the first row, the lines branch out from C to V to C and from C to P to V. In the second row, the lines branch out from P to C to V and from P to V to P. In the last row, the lines branch out from V to C to P and from V to P to C.
A tree diagram is shown. The lines branch out to C, P, and V. In the first row, the lines branch out from C to V to P and from C to P to V. In the second row, the lines branch out from P to C to V and from P to V to C. In the last row, the lines branch out from V to C to P and from V to P to C.
A tree diagram is shown. The lines branch out to C, P, and V. In the first row, the lines branch out from C to V to P and from C to P to V. In the second row, the lines branch out from P to C to P and from P to V to C. In the last row, the lines branch out from V to C to V and from V to P to C.
A tree diagram is shown. The lines branch out to C, P, and V. In the first row, the lines branch out from C to V to P and from C to P to C. In the second row, the lines branch out from P to C to V and from P to V to C. In the last row, the lines branch out from V to C to P and from V to P to V.

Answer 9

should look something like this...

(the basic principle is not to repeat any letters along the same branch)

Answer 10

okay so then what do we do?
@Vocaloid

Answer 11

we start C, P, and V... this represents the first cake. next we draw two branches from each, representing the two possibilities for the next cake

Answer 12

then for each branch we use the one that's left



the order of the branches might be different but the principle is the same...