Mathematics
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OpenStudy (anonymous):
Determine the standard form of the equation of the line that passes through (9, -4) and (6, 4)
Haaaaalp
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OpenStudy (misty1212):
HI!!
OpenStudy (anonymous):
Hi!
OpenStudy (misty1212):
first we need the slope, because no matter what, if you want the equation of a line you need to have the slope
do you know how to find ti?
OpenStudy (anonymous):
that would be -4+4 over 9+4 right?
OpenStudy (misty1212):
not quite
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OpenStudy (misty1212):
you want to subtract, not add
OpenStudy (anonymous):
Oh, okay. Hold on Lemme try.
OpenStudy (misty1212):
kk
OpenStudy (anonymous):
ok so its -8/5 ??
OpenStudy (misty1212):
hmm \(9-6=?\)
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OpenStudy (anonymous):
oh dang! I was doing -4. My bad. So it's 4.
OpenStudy (misty1212):
lets go slow
OpenStudy (anonymous):
Yes
OpenStudy (misty1212):
(9, -4) and (6, 4)
OpenStudy (misty1212):
first we do it the think way, then we do it the math teacher way
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OpenStudy (anonymous):
Okay, it's like the third day of school. My brain doesn't work yet! sorry ahah.
OpenStudy (misty1212):
from 6 to 9 in the x is right 3 units
from 4 to -4 in the y is down 8 units
right 3, down 8
slope is \[-\frac{8}{3}\]
OpenStudy (anonymous):
okay, yes.
OpenStudy (misty1212):
now the math teacher way
\[\frac{y_2-y_1}{x_2-*x_1}=\frac{-4-4}{9-6}=-\frac{8}{3}\] or
\[\frac{4-(-4)}{6-9}=\frac{8}{-3}=-\frac{8}{3}\] either way
OpenStudy (anonymous):
okay, got it.
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OpenStudy (misty1212):
who goes to school in the middle of august?
OpenStudy (misty1212):
ok no matter, now we have the the slope, and we can use the"point slope" formula because we have two points to choose form
OpenStudy (anonymous):
Everyone where I'm from starts in August. I know some places in California start later.
so y=mx+b?
OpenStudy (anonymous):
wait, thats not right.
OpenStudy (misty1212):
no that is the "slope intercept " form we are not there yet
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OpenStudy (anonymous):
y-y1 = m (x-x1)
OpenStudy (misty1212):
yeah that one
OpenStudy (anonymous):
Okay so
-4 - 4 = -8/3 (9 - 6) ?
OpenStudy (misty1212):
ooh no
OpenStudy (misty1212):
the x and y in the formula are the variables you see in the answer
only the \(x_1\) and \(y_1\) are numbers (as well as m )
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OpenStudy (misty1212):
you put numbers everywhere
OpenStudy (anonymous):
oh. gosh ok.
y+4= -8/3 (x-9)
OpenStudy (misty1212):
looks a lot better now
OpenStudy (anonymous):
subtracting a negative turns it into an addition basically, right?
OpenStudy (misty1212):
right
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OpenStudy (misty1212):
now you should probably put it in "slope intercept" form aka solve for y
OpenStudy (misty1212):
you know how to do that? takes the same two steps every time
OpenStudy (anonymous):
Move the 4 to the other side?
OpenStudy (misty1212):
no not yet
OpenStudy (misty1212):
first distribute the \(-\frac{8}{3}\) on the left
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OpenStudy (anonymous):
oh yeah. so I multiply it or add it to the left?
OpenStudy (misty1212):
multiply
OpenStudy (misty1212):
\[y+4=-\frac{8}{3}+24\] if my arithmetic is correct
OpenStudy (misty1212):
then don't "move the 4" subtract 4
OpenStudy (misty1212):
sorry, typo there i meant \[y+4=-\frac{8}{3}x+24\]
i dropped the x by mistake
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OpenStudy (anonymous):
wait, where did 24 come? distributing the slope on the right side?
OpenStudy (misty1212):
yeah
OpenStudy (misty1212):
cancel the 3's
OpenStudy (misty1212):
\[-\frac{8}{3}\times (-9)=3\times 8=24\]
OpenStudy (anonymous):
Okay, I understand.
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OpenStudy (misty1212):
so now we are at
\[y+4=-\frac{8}{3}x+24\] subtract 4 from both sides and you are done
OpenStudy (anonymous):
y=-8/3x+20
OpenStudy (misty1212):
yup
OpenStudy (misty1212):
took a while but i hope it is ok
OpenStudy (anonymous):
Is that the final answer?
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OpenStudy (anonymous):
Thanks by the way (:
OpenStudy (misty1212):
yeah it is the "final answer" as they say on tv you are quite welcome \[\color\magenta\heartsuit\]
OpenStudy (anonymous):
haha, of course! I'll give you a medal.
OpenStudy (misty1212):
thanks!