@shalante can you help me with a problem
i just need help graphing something ..
Post it
okay so it says Using the two functions listed below, insert numbers in place of letters a,b,c and d so that f(x) and g(x) inverses \[f(x) = \frac{ x+a}{ b }\]
and g(x) - cx - d
for this part, i chose to do this f(x) = 2x + 5
to find g(x) we would have to find the inverse of f(x) right?
becaue i did it that way, and got this: y=2x+5 (because i replaced f(x) and y)
am i correct so far?
f(x) has to be (x+any number)/a different number.
i got x-5=2y/ 2
and then after simplifying that i got y = x-5 / 2
then where it says to evaluate g(x) i wasnt sure but this is how i did it:
is it g(x)-cx-d or g(x)=cx-d?
g(f(x)) = (2x+5)-5 / 2
its g(x)=cx-d
wait im sorry i didnt include the parts
for part 1 it said show the work that the inverse of f(x) is g(x)
2nd*
the third part says to show my work evaluating g(x) and thats how i got the last ones
i got g(f(x)) = (2x+5)-5 / 2 , because i thought i would have to replace f(x) with the X in the g(x) ... if that makes any sense
and at the end its asking me to graph it and im lost o_o
what do you have to graph? f(g(x))?
yes ..
i got this far : \[g(f(x)) = \frac{ (2x+5)-5 }{ 2 }\]
but im not sure how to graph it now
Can you type out the whole problem correctly in one box to make sure?
thats it....
tell me part 1,2,3 exactly from your assignment
I need to know all the parts to do the steps correctly.
Task 1 Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses. f(x)= x+a / b g(x)=cx−d Part 2. Show your work to prove that the inverse of f(x) is g(x). Part 3. Show your work to evaluate g(f(x)). Part 4. Graph your two functions on a coordinate plane. Include a table of values for each function. Include 5 values for each function. Graph the line y = x on the same graph.
And if you go to the top, thats how i did the work...
Part 1 Let a=5, b=2,c=2,d=5 so |dw:1440132478788:dw| Part 2 |dw:1440132298809:dw| |dw:1440132437924:dw| Part 3:|dw:1440132646061:dw| |dw:1440132696527:dw|
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