Question

anyone can help me with this conversion..

Answer 1

3.A certain fuel-efficient hybrid car gets gasoline mileage of 55.0 mpg (miles per gallon). (a) If you are driving this car in Europe and want to compare its mileage with that of other European cars, express this mileage in km/L (L = liter). Use the conversion factors in Appendix E. (b) If this car's gas tank holds 45 L, how many tanks of gas will you use to drive 1500 km?

4.In the fall of 2002, a group of scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237 is about 60 kg. The critical mass of a fissionable material is the minimum amount that must be brought together to start a chain reaction. Neptunium-237 has a density of 19.5g/cm^3.

What would be the radius, r, of a sphere of neptunium-237 that has a critical mass?

5.With a wooden ruler you measure the length of a rectangular piece of sheet metal to be 12 mm. you use a micrometer caliper to measure the width of the rectangle and obtain the value 5.98 mm. Give your answers to the following questions to the correct number of significant figures:

a. What is the area of the rectangle?
b. What is the ratio of the rectangle’s width to its length?
c. What is the perimeter of the rectangle?
d. What is the difference between the length and width?
e. What is the ratio of the length to the width?

Answer 2

@Michele_Laino can you help me here ^^

Answer 3

exercise #4
the relationship between density, volume and mass, is:
\[\Large \delta = \frac{m}{V}\]
where \delta is density.
Now, please, write the inverse formula for volume V

Answer 4

Question 5,a) 12*5.98
b)
5.98/12
c) 12+12+5.98+5.98
d)12-5.98
e)12/5.98

Answer 5

@ggg123
If you liked my response don't forget to fan and medal. Thank you.

Answer 6

can you show me the solutions @arindameducationusc

Answer 7

Question 4, sorry. I could not do....
@Michele_Laino
Here, Radius is being asked? What could possibly be the relation?

Answer 8

@ggg123 sorry I tried Question 4, but could not.....

Answer 9

from my previous formula, we have:
\[V = \frac{m}{\delta }\]
now, the volume of a sphere, whose radius is r, is:
\[V = \frac{{4\pi }}{3}{r^3}\]
so, after a substitution, we get:
\[\frac{{4\pi }}{3}{r^3} = \frac{m}{\delta }\]
hence, solving for r, we can write:
\[r = \sqrt[3]{{\frac{3}{{4\pi }}\frac{m}{\delta }}}\]
substituting your numeric data, we get the requested radius

Answer 10

Nice @Michele_Laino

Answer 11

thanks!! @arindameducationusc