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Mathematics 13 Online
OpenStudy (anonymous):

Please help will fan and medal!!!!!!!!!!

OpenStudy (anonymous):

Two quadratic functions are shown. Function 1: f(x) = 4x2 + 8x + 1 Function 2: x g(x) −2 2 −1 0 0 2 1 8 Which function has the least minimum value and what are its coordinates? Function 1 has the least minimum value and its coordinates are (−1, −3). Function 1 has the least minimum value and its coordinates are (0, 1). Function 2 has the least minimum value and its coordinates are (−1, 0). Function 2 has the least minimum value and its coordinates are (0, 2).

OpenStudy (anonymous):

@welshfella

OpenStudy (welshfella):

the least value for g(x) as seen from the table is at (-1,0)

OpenStudy (welshfella):

now you need to find the coordinates of the minimum value of 4x^2 + 8x + 1 do you know how to do that ?

OpenStudy (anonymous):

No. I am just learning it.

OpenStudy (welshfella):

you can do it by converting to vertex form is that what you are learning?

OpenStudy (welshfella):

I dont know what grade you are working at

OpenStudy (welshfella):

the general form for the vertex is a(x - b)^2 + c

OpenStudy (welshfella):

you perform what is called 'complete the square' on the terms in x^2 and x

OpenStudy (anonymous):

ok.

OpenStudy (welshfella):

??

OpenStudy (anonymous):

ok so the answer is C?

OpenStudy (welshfella):

4x2 + 8x + 1 = 4(x^2 + 2x + 1/4) = 4 [(x + 1)^2 - 3/4] so the minimum values is at the coordinates (-1 , 4*-3/4) = (-1,-3)

OpenStudy (welshfella):

so compare this wit (-1,0) and you'll see which has minimum value

OpenStudy (welshfella):

- the second coordinate will give you the minimum value (because second cood is the value of the function)

OpenStudy (welshfella):

ok?

OpenStudy (anonymous):

So the answer is D? Correct?

OpenStudy (welshfella):

No it cant be D because the coordinates re not (0,2)

OpenStudy (welshfella):

compare (-1,0) and (-1,-3) thats all you need do

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