MEDAL = FAN What value of c solves the equation?
remember this exponent rule \[\huge\rm x^{-m}=\frac{ 1 }{ x^{-m} }\] if there is negative exponent then you should `flip` the fraction.
what do you men by flip the fraction?
mean**
I know it was just a type-o :p \[x^{-m}=\frac{1}{x^{\color{red}m}}\]
like in this example x^{-m} is same as x^{-m} over one \[\huge\rm \frac{ x^{-m }}{ 1 }= \frac{ 1 }{ x^m }\] in other words reciprocal of x^{-m}/1 is 1/x^m
2/3 when you flip it you will get 3/2 right ?
Yes.
So if I flip, I will get \[\frac{ 16 }{ 1 }\]
If that's what you mean
that's exactly how u should flip the fraction but i meant to say that c should be negative so that's 4^c is equal to 1 over 16
\[\huge\rm \frac{ 4^{-c} }{ 1 }= \frac{ 1 }{ 16 }\] \[\frac{ 4^{-c} }{ 1 } = ?\]
And how do i figure out 4-^c?
let's do the other way \[\huge\rm 4^c =16\] reciprocal of 1/6 is 16 now 4 to the what power = 16?
1/16**
the 3rd?
4^3 is same 4 times 4 times 4 which is not equalto 16
my mistake, 4^2.
does c = 2?
actually my bad first we write it in exponent form and then we should flip it i'm sorry \[\huge\rm 4^c=\frac{ 1 }{ 4^2 }\] now flip the fraction when you do that sign would change
\[\huge\rm 4^c= 4^{-2}\] now cancel out 4
C=-2?
yes right
now just to check ur answer substitute c for -2 \[\frac{ 4^{-2} }{ 1 }=\frac{ 1 }{ 16 }\]both sides re equal good to go! remember there is negative exponent so don't forget to flip the fraction :P
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