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OpenStudy (mathmath333):
\(\large \color{black}{\begin{align}
& \normalsize \text{There are \(10\) points in a plane of which \(4\) are collinear. }\hspace{.33em}\\~\\
& \normalsize \text{No other \(3\) points are collinear.}\hspace{.33em}\\~\\
& \normalsize \text{Find the number of lines that can be drawn .}\hspace{.33em}\\~\\
\end{align}}\)
ganeshie8 (ganeshie8):
is the answer \(\dbinom{6}{2} + 6*4\) ?
OpenStudy (mathmath333):
10C2-4C2+1
ganeshie8 (ganeshie8):
right, both are same just a +1 is missing in my earlier reply
OpenStudy (mathmath333):
how u got that
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ganeshie8 (ganeshie8):
forget about 4 collinear points
ganeshie8 (ganeshie8):
then you have 6 points,
you know that any two points determine a line
so how many lines can you make using 6 points ?
OpenStudy (mathmath333):
6c2
ganeshie8 (ganeshie8):
next, from each of these 6 points, you can draw a line to each of the 4 collinear points, yes ?
OpenStudy (mathmath333):
yes
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ganeshie8 (ganeshie8):
|dw:1440183836929:dw|
ganeshie8 (ganeshie8):
how many lines can you draw from those 6 points to those 4 collinear points ?
OpenStudy (mathmath333):
6C4
ganeshie8 (ganeshie8):
|dw:1440183971999:dw|
ganeshie8 (ganeshie8):
nope, notice that from each of those 6 points, you can draw exactly 4 lines to those collinear points
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OpenStudy (mathmath333):
4*6
ganeshie8 (ganeshie8):
Yes, so far the count is \(\dbinom{6}{2}+4*6\)
can you guess the one line that is missing ?