Question

It has been 4 hours. My hope is slowly diminishing. Please MAYDAY! MAYDAY!

Find the equation of a line containing the points S(-3,4) and T(6,-7) in slope-intercept, standard, and point-slope form.

Answer 1

what slope did you get?

Answer 2

actually I think it's -9/11

Answer 3

yes

Answer 4

no you had it right the first time

Answer 5

oh -11/9

Answer 6

So what do I do from here?

Answer 7

\[\Large m = \frac{y_2-y_1}{x_2-x_1}\]
\[\Large m = \frac{-7-4}{6-(-3)}\]
\[\Large m = \frac{-7-4}{6+3}\]
\[\Large m = \frac{-11}{9}\]

Answer 8

now you use one of the points along with the slope

Answer 9

Yes thank you for that.

Answer 10

and plug them into the point slope form

\[\Large y - y_1 = m(x-x_1)\]

Answer 11

how do I find the y intercept?

Answer 12

\[\Large y - y_1 = m(x-x_1)\]
\[\Large y - y_1 = -\frac{11}{9}(x-x_1)\]
\[\Large y - 4 = -\frac{11}{9}(x-(-3))\]
\[\Large y - 4 = -\frac{11}{9}(x+3)\]
In Step 2, I plugged in the slope
In Step 3, I plugged in one of the given points. In this case, I used (-3,4)

Answer 13

so hopefully you see how I got the point slope form equation

Answer 14

Wow, brilliant!

Answer 15

but how do I find the b value in slope-intercept form?

Answer 16

now isolate y and convert the equation into y = mx+b form

Answer 17

also you'll have to distribute the -11/9 through

Answer 18

Alright thanks!

Answer 19

as for standard form, you have to convert to Ax + By = C form

Answer 20

A,B,C are whole numbers

Answer 21

Yes I understand how to do this from there! Thanks so much, really appreciate it.

Answer 22

you're welcome