ALGEBRA II HELP: Which of the following is the conjugate of 10 − 3i?
change the sign in front of the imaginary part to find the conjugate
(a + bi and (a - bi) are conjugates
It would be 10+3i For example Conjugates: 3-2i, 3+2i
remember part of the general quadratic formula \[-b \pm \sqrt{b^2 - 4ac}\] so if you think about \[3 \pm \sqrt{-4} = 3 \pm 2i\] so the integer doesn't change its just the sign of the imaginary part
its also like the difference of 2 squares how do you get a 2 term quadratic (a -b)(a +b) = a^2 - b^2
sorry, my wi-fi went out for awhile @campbell_st @twistnflip @peachpi
so i would want to do the opposite for this one?
what is the first step?
Yes the conjugates are easy. just switch the sign from positive to negative or vice versa. Here the conjugate is 10+3i
so it would be 13i?
wow I'm being stupid
Nope do you have answer choices. It wouldn't be 13i because you can't add the two terms because one has a variable and the other does not lol
The answer is 10 + 3i <-- Final answer
i get it the question was just asking for the conjugate so its 10+3i
my answer choices are
10 + 3i 10 − 3i 3 + 10i 3 − 10i
a.
Make sense?
thanks for helping me better understand, everyone!
yep, makes perfect sense
Join our real-time social learning platform and learn together with your friends!