WILL AWARD MEDAL How do you solve the inequality (x^2)(e^x) ln x 0?? @nincompoop @Nnesha @zepdrix @jagr2713

Question

WILL AWARD MEDAL How do you solve the inequality (x^2)(e^x) ln x > 0?? @nincompoop @Nnesha @zepdrix @jagr2713

zzr0ck3r · Answer

well $e^x>0$ for all $x$, $x^2>0$ for all $x\ne 0$ and $\ln(x)>0$ for all $x>1$.

So ?

zzr0ck3r · Answer

hint: the $ln(x)$ factor trumps them all.

anonymous · Answer

sorry i don't really understand where this is going.

anonymous · Answer

@zzr0ck3r

anonymous · Answer

These are things we can do without affecting the direction of the inequality: Add (or subtract) a number from both sides. Multiply (or divide) both sides by a positive number. Simplify a side. 

Hoped this helped :)

zzr0ck3r · Answer

What I am saying is that 

$x^2e^x\ln(x)>0 \iff \ln(x)>0\iff x>1$