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Mathematics 15 Online
OpenStudy (anonymous):

quick algebra question?

OpenStudy (anonymous):

the area of a square is 5 more than its perimeter. find the length of a side.

OpenStudy (anonymous):

my work so far: 4r=r^2+5 r^2-4r+5=0 then I am supposed to factor? I cannot figure out how to factor this! I literally tried every possible way.. :( someone please help me?

OpenStudy (anonymous):

Good morning I think I mIght be able to assist

OpenStudy (anonymous):

I bRelieve your doing it correctly so far

OpenStudy (anonymous):

awesome thanks!

OpenStudy (anonymous):

Hey that's what I'm here for

OpenStudy (anonymous):

Brb

OpenStudy (anonymous):

Ok I'm back Olivia

OpenStudy (anonymous):

And thX for the compliment I appreciate it

OpenStudy (anonymous):

ok im here! :)

OpenStudy (amistre64):

Are we reading it correctly? Area = Perimeter + 5 how do we define area and perimeter of a square ?

OpenStudy (anonymous):

yes I believe so.. And im not sure, I honestly just follow the practice problems along with the actual problem to solve it. :/

OpenStudy (amistre64):

area, is 5 more than perimeter area = perimeter + 5 area = r^2, and perimeter is 4r youre initial setup seems flawed to me

OpenStudy (anonymous):

ok, like i said I was just following the practice problem so the way I set it up is probably wrong. how would you set it up?

OpenStudy (amistre64):

the way i have already set it up ... area = perimeter + 5

OpenStudy (anonymous):

ok but how would i solve that? thanks for ur help btw!

OpenStudy (amistre64):

the area of a square is 5 more than its perimeter ^^^ = ^ ^^^ ^^^^^^^ r^2 = 4r + 5 area = perimeter + 5 ------------------ but you setup as: 4r = r^2 + 5 perimeter = area + 5 ------------------- solving it is just finding the solutions to the quadratic, factor if you can (it most likely factorable)

OpenStudy (amistre64):

r^2 -4r -5 = 0

OpenStudy (anonymous):

ok give me a second to factor it

OpenStudy (amistre64):

any thoughts about how we could factor it?

OpenStudy (amistre64):

k

OpenStudy (anonymous):

(r+1)(r-5)=0

OpenStudy (amistre64):

you did fine with the factoring

OpenStudy (anonymous):

ok, so it would solve to be r=-1, and r=5...so it would be 5 units?

OpenStudy (amistre64):

5 is the workable length, -1 is just a extra value that doesnt fit with the expected domain and can be ignored 5 is fine

OpenStudy (anonymous):

yay is what right! thanks so much for your help it was a lot easier than i thought :p

OpenStudy (amistre64):

ive had years of practice :) youll do fine

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