Solve x2 + 6x + 7 = 0. x = −1 and x = −5 3 plus or minus square root of 2 negative 3 plus or minus square root of 2 quantity of negative 3 plus or minus square root of 2 all over 2
apply the quadratic formula \[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] plugin a ,b ,c values \[\huge\rm Ax^2+Bx+C\]quadratic equation where a=leading coefficient b=middle term c=constant term
what is a in that equation a= ? b=? c=?
1
yes right a =1 b= ? c=??
b =middle term c=constant
6x
7
just the coefficient so b=6 a=1,b=6, c=7 now substitute a , b ,c for their values into quadratic formula
okay
This method works just fine. However, in this problem, it would be easier to factor.
would it be d?
it's not factorable.
and no what did you get 't the numerator ?
-3 plus or minus the suare root of -22
hmm no how did you get -22 ???
i had done 6- (4)(1)(7), but i realize 6 needs to be squared, so i now get -3 +- square root of 2?
2
ugghhhhh nvm sorry latex arn't working
what...?
yes that's right take square of 6
i was trying to type that into the equation tool but it's not loading
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