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Mathematics 19 Online
OpenStudy (anonymous):

Solve x2 + 6x + 7 = 0. x = −1 and x = −5 3 plus or minus square root of 2 negative 3 plus or minus square root of 2 quantity of negative 3 plus or minus square root of 2 all over 2

Nnesha (nnesha):

apply the quadratic formula \[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] plugin a ,b ,c values \[\huge\rm Ax^2+Bx+C\]quadratic equation where a=leading coefficient b=middle term c=constant term

Nnesha (nnesha):

what is a in that equation a= ? b=? c=?

OpenStudy (anonymous):

1

Nnesha (nnesha):

yes right a =1 b= ? c=??

Nnesha (nnesha):

b =middle term c=constant

OpenStudy (anonymous):

6x

OpenStudy (anonymous):

7

Nnesha (nnesha):

just the coefficient so b=6 a=1,b=6, c=7 now substitute a , b ,c for their values into quadratic formula

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

This method works just fine. However, in this problem, it would be easier to factor.

OpenStudy (anonymous):

would it be d?

Nnesha (nnesha):

it's not factorable.

Nnesha (nnesha):

and no what did you get 't the numerator ?

OpenStudy (anonymous):

-3 plus or minus the suare root of -22

Nnesha (nnesha):

hmm no how did you get -22 ???

OpenStudy (anonymous):

i had done 6- (4)(1)(7), but i realize 6 needs to be squared, so i now get -3 +- square root of 2?

OpenStudy (anonymous):

2

Nnesha (nnesha):

ugghhhhh nvm sorry latex arn't working

OpenStudy (anonymous):

what...?

Nnesha (nnesha):

yes that's right take square of 6

Nnesha (nnesha):

i was trying to type that into the equation tool but it's not loading

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