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Mathematics 11 Online
OpenStudy (anonymous):

???

OpenStudy (irishboy123):

by linear approximation, do you mean \(V = \frac{4}{3} \pi r^3\), \(\Delta V = \frac{dV}{dr}\Delta r\) ?

OpenStudy (anonymous):

Would I derive the first one?

OpenStudy (welshfella):

yes differentiate (4/3) pi r^3 which is the formula for the volume of the sphere

OpenStudy (anonymous):

4pir^2

OpenStudy (welshfella):

correct

OpenStudy (anonymous):

And then what

OpenStudy (irishboy123):

then this https://gyazo.com/286b458598def9d5b57be9a7393d584f

OpenStudy (welshfella):

you know the value of r and delta r - Just plug them in and calculate

OpenStudy (anonymous):

36pi

OpenStudy (anonymous):

?????

OpenStudy (irishboy123):

correct to within 0.01 inch in maths speak is: \(\Delta r = \pm 0.01\) you got \(\frac{dV}{dr} = 4 \pi r^2\) yourself, so finish the job

OpenStudy (welshfella):

36pi is correct for the value of 4 pi r^2 now you plug is the +/- 0.01

OpenStudy (welshfella):

* plug in

OpenStudy (anonymous):

.36

OpenStudy (welshfella):

no

OpenStudy (anonymous):

.036

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