Question

How do you solve:
2/3= x+7/ 3x

Answer 1

is it \[\frac{ x+7 }{ 3x } \rm ~or~x+\frac{ 7 }{ 3x }\]

Answer 2

the first one

Answer 3

alright good \[\huge\rm \frac{ 2 }{ 3 }=\frac{ x+7 }{ 3x }\] cross multiply

Answer 4

here is an example \[\huge\rm \frac{ a }{ b }=\frac{ c }{ d}\]\[\rm ad=bc\]

Answer 5

Do you know how @Amineh0923

Answer 6

Hint:
2/3 = x+7/3x
2(3x) = 3(x+7)

Answer 7

Now distribute...

Answer 8

that's better ;)

Answer 9

so was I right? its 6x / 3x+7 ? @twistnflip

Answer 10

eek, try again:
2/3 = x+7/3x
2(3x) = 3(x+7)
You are missing one thing try one more time

Answer 11

6x= 3x+21?

Answer 12

there you go, awesome. Now do you know how to solve for x?

Answer 13

I think, I add 6x and 3x because they are like terms which leaves me with 9x = 21, then I divide each side by... oops that's not right :(

Answer 14

yep you are close though. instead (this is how i was taught) alway cosine terms by subtracting the smallest term from the biggest term. so here subtract 3x from 6x

Answer 15

combine not cosine

Answer 16

so.. 6x= 3x + 21
-3x -3x
3x= 21
/3 /3

x=7?

Answer 17

there you go!! awesome job

Answer 18

thanks so much! I would fail this on the test if u hadn't cleared that up ;) :P

Answer 19

no problem anything else? post a new question