Question

Find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2.

Answer 1

@ganeshie8 @Loser66

Answer 2

least favorite problems lol, mind if I help?

Answer 3

Sure!

Answer 4

standard form: y = a(x-h)^2 + k

Answer 5

BTW did my help earlier help you?

Answer 6

yes quite a bit actually, sorry i didn't help so much I was a bit confused. but I will make it up to you now

Answer 7

lol kind of failed but you get the point. so the vertex is halfway between these points.
so the vertex is actually at (0,0)
in the standard from (h,k) is the vertex following so far?

Answer 8

Oh no its fine I understand!

Answer 9

y = a(x-h)^2 + k
y = a(x-0)^2 + 0
y = a(x)^2
a = 1/4c
c is 2, the difference between the focus and the vertex
so a = 1/(4*2)
a = 1/8
y = 1/8 (x)^2

Answer 10

Focus (0,-2) hence p=-2, right?
So just plug it in x^2=4py

Answer 11

@Loser66
hey my final answer is
y = 1/8(x)^2
Is that right?

Answer 12

Same

Answer 13

awesome so do you get that @PHUNISH

Answer 14

Oh okay thanks guys1

Answer 15

no problem

Answer 16

But, to focus, direct fix oinformat6, you should apply the formula